(7/x)+(4/3x^2)

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Solution for (7/x)+(4/3x^2) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/3)*x^2+7/x = 0

4/3*x^2+7*x^-1 = 0

x^-1*(4/3*x^3+7) = 0

4/3*x^3 = -7 // : 4/3

x^3 = -21/4

x^3 = -21/4 // ^ 1/3

x = -(21/4)^(1/3)

1/x = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -(21/4)^(1/3)

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